ASAP HELP!! In triangles DEF and OPQ, ∠D ≅ ∠O, ∠F ≅ ∠Q, and segment DF ≅ segment OQ. Is this information sufficient to prove triangles DEF and OPQ congruent through SAS? Explain your answer.

WILL GIVE BRAINLESIT

I THINK they are congruent because you said "∠D ≅ ∠O, ∠F ≅ ∠Q, and segment DF ≅ segment OQ."

Step-by-step explanation:

If you find my answer helpful

Pls consider marking my answer as Brainliest! It would mean a lot!

No this information is not sufficient to prove triangles DEF and OPQ are congruent through SAS because this information doesn't provide another pair of congruent sides in order to be SAS. Another reason this information is inefficient, they provided two pairs of congruent angles rather than two congruent sides and one congruent angle.  This information provided shows angles DEF and OPQ being congruent through ASA rather than SAS. There are two angles that are congruent, provided by the information above, and both angles are set on a congruent side making it ASA.

Step-by-step explanation:

DEF and OPQ

Angle D =Angle O —Angle

Line DF = Line OQ—Side

Angle F= Angle Q—Angle

The information provided shows DEF and OPQ through ASA rather than SAS. Therefore, the following information is not sufficient to prove DEF and OPQ through SAS.

(Below is not the answer just saying if they wanted to prove DEF and OPQ through SAS it would be this)

—If they wanted to prove it through SAS the information should have stated:

DEF and OPQ

Line EF is congruent to Line PQ—Side

Angle F is congruent to Angle Q—Angle

Line DF is congruent to Line OQ—Side 

Making triangle DEF and OPQ congruent through SAS. 

the number of possible outcomes that do not show a 1 on the first spinner and show the number 4 on the second spinner is 2.

spinner 1 spinner 2

1                     1

1                     2

1                     3

1                     4

2                   1

2                   2

2                   3

2                   4   = not 1, and 4

3                   1

3                   2

3                   3

3                   4 = not 1, and 4

only 2 outcomes have passed the given condition.

step-by-step explanation: