What is the domain of the function graphed at the right?

idk srrry

Step-by-step explanation:

a

Step-by-step explanation:

think of domain as left to right

you can see from the left that there is an open dot on the x coordinate -3

since it's an open dot, it does not include -3, so < will be used

the function extends to the x coordinate 5, and since it's a closed dot, it will include 5, so ≤ is used

if the eqn of the parabola is f(x) = (x-4)(x+2), we need to mult. this out to find the coordinates of the vertex.

then f(x) = x^2 + 2x - 4x - 8, and f(x) = x^2 - 2x - 8.

one way in which you can find the vertex is to calculate x = -b / (2a).   here, that comes to

        )

x = = 1.   f(1) = 1^2 - 2(1) - 8 = - 9.   vertex is at (1, -9).

        2(1) 

find another point on the curve:   let x=0, for which y=-8.   then (0, -8) is on the curve.   plot the vertex and this point and draw a smooth parabola thru both.

hope this

the answer is a i belaeve atleast thats what my calculator just gfave me

step-by-step explanation: