Shares in stock of a new company are selling for $3.75 per share. An investor has $800. Which inequality can be solved to show the number of shares s he can buy?

Given:

Price of each share = $3.75

Total amount invertor has = $800

To find:

The inequality that can be solved to show the number of shares s he can buy.

Solution:

Let x be the number of shares he can buy.

Price of 1 share = $3.75

Price of x shares = $3.75x

An investor has $800.

The price of x shares must be less than or equal to the amount he has. So,

Divide both sides by 3.75.

So, the maximum possible integer value of x is 213.

Therefore, the equation inequality is and he can buy 213 shares.

x = ± 6i

step-by-step explanation:

x^2 = -36

take the square root of each side

sqrt(x^2) = sqrt(-36)

we know sqrt(ab) = sqrt(a) sqrt(b)

x = ±sqrt(36) sqrt(-1)

we know that sqrt (-1) = i

x = ± 6i

i dont know sorry

step-by-step explanation: