The sum of two consecutive odd integers is 20 less than four times the smaller of two integers. which of the following equations could be used to find the smaller integer, n? (1) (n+1)+(n+3)=20-4n
(2) n+(n+2)=4n-20
(3) (n+3)+n=20-4n
(4) n+(n+2)=4(n-20)

i can't solve unless i know what the line is

step-by-step explanation:

welcome to/p>

3100

step-by-step explanation:

it is definatly the 3rd one. very much looks like it, for a good chance, the third one would be best for you.

8(4)^8=72^feet to say that the total can conclude to 8(4) which as you know would mean 8 x 4. that equals 32w. 32^ could make a 72 answer as well. but your coefficent will remain w so your answer is 72w.

you!

if you need more with your math, visit khan academy where we give videos and tutorials   on everything math. we are efficent in our work.

you,

from,

the khan academy team