Consider the following information: Observations 1 2 3 4 5 6 Num. of defects 10 18 13 15 9 12 The number of runs above and below the sample median is:

There are 3 runs above and below the sample mean

Step-by-step explanation:

From  the given information; we have a table that can be computed as:

Observations              1      2       3      4     5     6

Number of defects     10     18    13    15     9     12

If we sort the order in ascending order; we have:

Observations              5      1       6      3     4     2

Number of defects     9     10    12    13     15     18

The median is the  middle number; here the integers are even :

Thus, the median is  (12 + 13)/2 = 12.5

We need to make counts from the table given above to determine if they are below or above the median

Observations              1      2       3      4     5     6

Number of defects     10     18    13    15     9     12

Above(A) /Below (B)    B     A       A     A    B      B

To count for the number of runs from the  beginning and when there is a change of runs from A to B; we have:  

Observations              1      2       3      4     5     6

Number of defects     10     18    13    15     9     12

Above(A) /Below (B)    B     A       A     A    B      B

Runs                             1        2      -      -      3      -

Therefore, from the analysis, there are 3 runs above and below the sample mean

x = ± 6i

step-by-step explanation:

x^2 = -36

take the square root of each side

sqrt(x^2) = sqrt(-36)

we know sqrt(ab) = sqrt(a) sqrt(b)

x = ±sqrt(36) sqrt(-1)

we know that sqrt (-1) = i

x = ± 6i

54 km / hours

step-by-step explanation:

we need to convert seconds to hours

60 seconds = 1 minutes

60 minutes = 1hour

15 m         60 second   60 minutes

  * *         = 54000 meters/ hour

second     1 minute             1 hour

now we need to convert meters to km

1000 m = 1 km

54000 m       1 km

*   = 54 km / hours

hour               1000m