Some car jacks are constructed like a collapsed rhombus. When used to raise a​ car, the rhombus is easily seen. If the sides of the rhombus are 15​", what is the maximum length of the​ shaft?

Complete question is;

Some car jacks are constructed like a collapsed rhombus. When used to raise a car, the rhombus is easily seen. If the sides of the rhombus are 15 inches, what is the maximum length of the shaft?

Maximum length of shaft = 30 inches

Step-by-step explanation:

To understand this clearly, I've attached a real life image of a car jack that's in the shape of a rhombus.

From the attached image, we can see that it has four sides which are equal in length.

Now, if this jack is collapsed, the shaft will just be like a straight line with a maximum length equal to twice a side of the rhombus which represents the maximum length of the diagonal.

Since we are told that one side of the rhombus is 15 inches, it means that the maximum length of shaft = 2 × 15 = 30 inches

i would say c is the best answer, hope it's right!

good luck! =)

cutie~

answer: ratio of volume of cone (with 3 times the height and equal diameter) to volume of cylinder is 2 to 1. the value of π is not used.

step-by-step explanation:

radius is diameter/2 = 4.

area of circle is π r^2.

volume of cylinder is height × area of base = hπr^2 = 3(4^2) π = 48π cubic inches.

not knowing the formula for volume of cone, i calculate it using calculus (which is for calculating things).

volume of cone is integral 0 to h area(y) dy. area(y) is π r(y)^2. r(y) runs r to zero as y runs zero to h, r(0) = r, r(h) = 0.

r(y) = r - r/h y

area(y) = π (r - r/h y)^2 = π (r^2 - 2r^2y/h + r^2y^2/h^2) = π r^2(1-2y/h+y^2/h^2)

antiderivative area(y) = π r^2 (y-y^2/h+y^3/(3h^2))

integral 0 to h = π r^2(h-h^2/h+h^3/(3h^2) - (0)) = π r^2(h - h + h/3) = π r^2(h/3) = π/3 r^2 h

volume of this cone is π/3(4^2)18 cubic inches.

= 6 16 π = 96π cubic inches.

cone has twice the volume, 96/48.

cone height is 6 times the cylinder.

ratio of volume formula: π r^2 cancels.

cone over cylinder ratio is 6h/3 to h, 2 to 1.