One of the two points Seamus used to determine the slope of his trendline was (0.00286,4.27). If the slope of his trendline is 8,749 K, what is the y-intercept of his trendline

c = -25017.87

Step-by-step explanation:

The slope of his trendline is 8,749 K

The two points that are used to find the slope of his trendline was (0.00286,4.27).

We need to find the y-intercept of his trendline. Slope of equation is given by :

y = mx +c

We need to find c.

Put y = 4.27, m = 8,749000 and x = 0.00286

c = y-mx

c = 4.27- 8,749000 (0.00286)

c = -25017.87

So, the y -intercept of his trendline is 25017.87

answer: (c) m∠qpo + (2x + 16)° = 180°

step-by-step explanation:

the opposite angles of a quadrilateral are supplementary.

so, ∠o + ∠q = 180°   and   ∠p + ∠r = 180°

since ∠r = 2x + 16°, we can use substitution as follows:

∠p + ∠r = 180°

∠p + (2x + 16)° = 180°