The area of rectangle is 120 m² and its breadth is 8 m. Find the perimeter of the rectangle.

• Area of rectangle = 120 m²

• Breadth = 8m

• perimeter of the rectangle .

As we know that ,

• Area of rectangle = L× B

=> 120 = L × 8

=> L = 120/8

=> L = 15

Length of the rectangle is 15m .

Now ,

• perimeter of rectangle = 2 (L+B)

=> perimeter of rectangle = 2 (15+8)

=> perimeter of rectangle = 2 ( 23)

=> perimeter of rectangle = 46

Hence, the perimeter is 46 m .

I hope it will help you.

Regards.

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3

y=x+9

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step-by-step explanation: