Does anyone know how to do this??

Step-by-step explanation:

i'll explain how to do 9), it is the same process for the rest

y = 2x - 1

thus the value of 'y' should be the same as the result of '2x - 1'

when x = 5, 2x - 1 = 2(5) - 1 = 9, Thus (x, y) = (5, 9)

when x = 2, 2x - 1 = 2(2) - 1 = 3 Thus (x, y) = (2, 3)

when x = 0, 2x - 1 = 2(0) - 1 = 1 Thus (x, y) = (0, 1)

so in the table we have

x        2x - 1      y         (x, y)

5          9          9         (5, 9)

2          3          3         (2, 3)

0          1           1          (0, 2)

we can now plot these values on a graph to look like so

graph them on a graphing calculator, press 2nd trace. select intersect. hit enter until it says answer. ti 84 works best

step-by-step explanation: