Question 2 (1 point) What is the equation in slope-intercept form of the line that passes through the point (-4,0) and is perpendicular to the line represented by y=-3x - 1? O a y - () = -(x + 4) Ob y - 0) = (x + 4) y - 4 = -x-0) y + 4 = (x - 0)

Step-by-step explanation:

Given parameters:

 Coordinate = (-4, 0)

Equation of the line given; y = -3x - 1

Unknown:

The equation of the line perpendicular to this = ?

Solution:

To find the equation of the line perpendicular to the given line, we need to obtain the value of the slope from this equation first.

  The slope of the perpendicular line will be the negative inverse of the one given;

  Every straight line can be written as;

                               y  = mx + c

Given line;

                               y = -3x - 1

  the slope of this line = -3

A perpendicular line to this line will have a slope of;

                          a negative inverse of (-3)

Now,

       Let us go ahead and find the intercept c;

    y = mx + c

    0 =   x (-4) + c

          c=

insert parameters:

       y =  x +  

Multiply through by 3;

        3y = x + 4

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step-by-step explanation:

see explanation

step-by-step explanation:

since the sequence is geometric there is a common ratio r between consecutive terms, that is

r = 4 ÷ - 2 = - 2

r = - 8 ÷ 4 = - 2

r = 16 ÷ 8 = - 2

the next term - 13 must be incorrect as it should be - 32 for the sequence to be geometric.

the first 4 terms are therefore geometric with common ratio r = - 2