If you place 35 points on a piece of paper so that no three points are in a line, how many line segments are necessary to connect each point to all the others?

595 line segments are necessary to connect each point to all the others.

Step-by-step explanation:

Consider the provided information.

The formula for the number of line segments between "n" non-collinear points is:

Segments

Here it is given that there are 35 points.

Substitute n = 35 in above formula.

Segments

Hence, 595 line segments are necessary to connect each point to all the others.

area = length x width

length = 2 x width

32 = 2 x width x width

32 = 2 x width^2

36 = width ^2  

width = 6

length = 12

area is 32

perimeter = 2 x 12 + 2 x 6 = 24 + 12 = 36

step-by-step explanation:

597

step-by-step explanation: