John took all his money from his savings account. He spent 198 on a radio and 4/12 of what was left on presents for his friends. Of the money remaining, John put 2/9 into a checking account and the last remaining 980 was left to charity. How much money did John originally have in his savings account?

John had $2088 originally in his savings accounts.

Step-by-step explanation:

Let John had $x originally in his saving account

He spent $198 on a radio. The remaining money = x - $198

4/12 of what was left, he spent on presents for his friends. Remainig money = x - 198 - 4/12*(x-198)

= (1 - 4/12) of (x-198)

= 2/3 of (x-198)

John then put 2/9 if his remaining money into a checking account.

Now, the remaining money = 2/3*(x-198) - 2/9 of (x-198)

= (1 - 2/9) * 2/3*(x-198)

= 7/9 * 2/3*(x-198)

= 14/27(x-198)

Money left with him = $980

14/27(x-198) = $980

x - 198 = $980 * 27 / 14

x - 198 = 1890

x = 1890 + 198

x = 2088

Hence, John had $2088 originally in his savings accounts.

hope this !

step-by-step explanation:

d = distance between moon and sun, which in this problem is the hypotenuse of a right triangle.  

the distance y is the side opposite to angle x in the right triangle.   use the definition of the sine function from basic trigonometry.

sin(x) = y/d ⇒

d = y/sin(x)

correct answer:

i^31 = -i