PLEASE HELP A rectangular pyramid has a height of 10 meters. The base measures 8 meters in length and 12 meters in width. Two different triangular cross sections are formed through the vertex and perpendicular to the base. What is the difference in the areas of the cross sections?
m²

step 1

find the area of the first cross section

area1=b1*h/2

b1=8 m

h=10 m

area1=6*10/2> 30 m²

step 2

find the area of the second cross section

area 2=b2*h/2

b2=12 m

h=10 m

area1=12*10/2> 60 m²

step 3

find the difference in the areas of the cross sections

difference=60-30> 30 m²

the answer is

30 m²

Step-by-step explanation:

i believe the answer is the polygon, heptagon.

hi there!

the answer to this question is d: 35

step-by-step explanation:

5 to the power of 2 is 25

2 multiplied by 5 is 10

then you add the 2 numbers and you get 35