Help please! Find the equation of a line perpendicular to y = 2x – 1 that contains the point (-5,0). Write the equation in slope-
intercept form

  y = -1/2x - 5/2

Step-by-step explanation:

y = 2x – 1

Current slope is 2, perpendicular is opposite inverse which is -1/2.

y-intercept through point (-5, 0):

y = mx + b

0 = -1/2(-5) + b

0 = 5/2 + b

b = -5/2

Use the perpendicular slope and b above to form new equation of line:

y = mx + b

y = -1/2x - 5/2

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step-by-step explanation: