What is the equation of the line that is perpendicular to y = negative two-thirds x + 4 and that passes through (–2,–2)? On a coordinate plane, a line goes through (3, 2), and (6, 0). A point is at (negative 2, negative 2). y = three-halves x minus StartFraction 10 Over 3 EndFraction y = three-halves x minus 5 y = three-halves x + 1 y = three-halves x minus two-thirds

c

step-by-step explanation:

there is vertical asymptote at x = 2 and x = 0

vertical asymptote occurs at the points where the denominator is 0. so we can say that

x = 2 occurs when there is a factor (x-2) in the denominator, and

x = 0 occurs when there is a factor "x" in the denominator

thus, the denominator of the equation would have "x * (x-2)", this is option c only. that's the correct answer.

x² + 11x + 18 < 0  

[-11 ± sqrt(121 - 72)]/2 = (-11 ± 7)/2  

solution: (-9, -2)

step-by-step explanation:

faster, im not sure why but i know it is faster

step-by-step explanation:

gym b charges $1.05 less per hour than gym a.