Need help fast! Algebra

5)y=2x   6)y=12x    7)y=3x-2    8)y=1/4x+2

Step-by-step explanation:

Look at the y-intercept first if crosses the origin then don't need to write anything. If it does you add it after the slope.

To find slope you can count how many units up or down it does and how many left or right.

Then write i as rise/run.

Hope this helps

c

step-by-step explanation:

it isn't d, because the interquartile range is from 27-57. and the interquartile range is basically half the data, it's pretty obvious.

it isn't b, because like i said earlier, the interquartile range is from 27-57. 57-27 is 30. the real range has to be longer

not a either. although it looks like it, 3/4 of the data is not greater than 27. but if c is wrong than this should be correct

the correct answer is c, because 13 is the point in which the plot starts

the circle graph is not a function.

step-by-step explanation:

the graph of the circle is not a function.

because for a graph to be a function, each value of x must give one value of y

in the circle, the values of x for -2< x< 2 each give 2 values of y.

hence this is not a function.