17. The area of the large square below is 49 centimetres squared. What are the side lengths of the shaded triangle?

12.25,12.25,7

Step-by-step explanation:

Formula of Area of square= length x breadth

In a square all side are equal as we all know that which means if the Area of the square is if we take the root of 49 it gives us 7 so the length and breadth of the square is equal to 7 as shown in my figure i uploaded. Please excuse my professional drawing skills ( pun intended :D)

The dotted lines i assume shows that sides are being bisected into two equal halves which means the whole side equals 7cm and the half is 7/2 equals 3.5cm so the bottom half side of the triangle is 7cm but the two slant heights we have to find we can find it by using phythogra's theorem

(Hypotnuse)^2=(Length^2) x (Breadth)^2

we need to find just one side of the hypotnuse/slant height then we multiply it by 2 which would gives us both of our hypotnuse sides so

(Hypotnuse)^2= (3.5)^2 x (3.5)^2

(Hypotnuse)^2=150.0625

Apply square root on both sides gives us

Since the traingle is covered by two slant height's the sides of the traignle are 12.25cm 12.25cm and 7cm

dd

step-by-step explanation:

dd

let's add {f(x)=x+1}f(x)=x+1 and {g(x)=2x}g(x)=2x together to make a new function.

f(x)+g(x) =(x+1)+(2x)=x+1+2x=3x+1

let's call this new function hh. so we have:

{h(x)}={f(x)}+{g(x)}{=3x+1}h(x)=f(x)+g(x)=3x+1

we can also evaluate combined functions for particular inputs. let's evaluate function hh above for x=2x=2. below are two ways of doing this.

method 1: substitute x=2x=2 into the combined function hh.

h(x)

h(2)

​    

=3x+1

=3(2)+1

=7

​ since h(x)=f(x)+g(x)h(x)=f(x)+g(x), we can also find h(2)h(2) by finding f(2) +g(2)f(2)+g(2).

first, let's find f(2)f(2):

f(x)

f(2)

​    

=x+1

=2+1

=3

​  

now, let's find g(2)g(2):

g(x)

g(2)

​    

=2x

=2⋅2

=4

​  

so f(2)+g(2)=3+4=\greend7f(2)+g(2)=3+4=7.

notice that substituting x =2x=2 directly into function hh and finding f(2) + g(2)f(2)+g(2) gave us the same answer!