If sin x= 1/3 and sec y= 5/4 where x and y lie between 0 and pi/2, evaluate sin(x-y)

        sin(x) = ¹/₃
sin⁻¹[sin(x)] = sin⁻¹(¹/₃)
                x ≈ 0.34°
                x = ¹⁷/₉₀₀₀π

   sec(y) = 1¹/₄
           1 = 1¹/₄cos(y)
         ⁴/₅ = cos(y)
cos⁻¹(⁴/₅) = cos⁻¹[cos(y)] 
     0.64 ≈ y
    ⁴/₁₁₂₅π = y

sin(x - y) = sin(¹⁷/₉₀₀₀π - ⁴/₁₁₂₅π)
sin(x - y) = sin(⁻¹/₆₀₀π)
sin(x - y) = -sin(¹/₆₀₀π)
sin(x - y) = -sin(³/₁₀)
sin(x - y) ≈ -0.3

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“exterior angles of triangles. an exterior (or external) angle is the angle between one side of a triangle and the extension of an adjacent side. try this drag the orange dots on any vertex to reshape the triangle.” look to get to the answer i explained what it means and other things i hope it you .