Three hundred feet of fencing is available for a rectangular pasture alongside a river, the river serving as one side of the rectangle (so only three sides require fencing). Find the dimensions yielding the greatest area. (Enter your answers as a comma-separated list.)

(150 feet,75 feet)

Step-by-step explanation:

Let

Length of rectangle pasture,l=y

Breadth of rectangle pasture,b=x

Fencing used=300ft

Fencing used=2x+y

300=2x+y

y=300-2x

Area of rectangle pasture=xy

Differentiate w.r.t x

Again, differentiate w.r.t x

Hence, the area is maximum at x=75

Width of rectangle pasture,x=75 feet

Length of rectangle pasture,l=300-2(75)=150 feet

Dimension of rectangle pasture=(l,b)=(150 feet,75 feet)

let y equal to

the total fare and x is the mile of taxi ride. so the equation is

y = 0.55x + 1.75

since susie has

$10 to spend for a taxi cab, so he can have

10 = 0.55x +

1.75

x = 15 miles of

taxi ride

so the system of

inequality is

10 < 0.55x +

1.75

x > 2