A local sporting goods store is planning to hire up to 24 temporary employees for its annual Black Friday Sale. Experienced workers (x) will be paid $20 per hour and produce 1.5 times the profit that an inexperienced worker produces. Inexperienced workers (y) get hired at $15 per hour. The store can pay up to $400 per hour for the temporary employees. How many of each type of worker can be hired to maximize profit?

8 experienced workers and 16 inexperienced workers

Step-by-step explanation:

Let x represent the number of experienced workers, y represent the number of inexperienced workers.

The store can hire up to 24 temporary employees, hence:

x + y ≤ 24

The store can pay up to $400 per hour, hence:

20x + 15y ≤ 400

Also, x, y > 0

The solution to the above problem is at (8, 16). Hence x = 8 and y = 16.

The profit of an experienced worker is 1.5 times the profit that an inexperienced worker. hence:

Profit = 1.5x + y

Profit = 1.5(8) + 16

Profit = 12 + 16 = 28

there are many solutions.

step-by-step explanation:

step 1: simplify both sides of the equation.

4x+6=4x^2+10x−4

step 2: subtract 4x^2+10x-4 from both sides.

4x+6−(4x^2+10x−4)=4x^2+10x−4−(4x^2+10x−4)

−4x^2−6x+10=0

step 3: factor left side of equation.

−2(2x+5)(x−1)=0

step 4: set factors equal to 0.

x=-5/2 or x=1

c

step-by-step explanation:

it would be see because your formula is f(x)=6x, so 6 times 1 is 6 and you go on and the best answer is c.