What are the steps for using a compass and straightedge to construct a line through point X that is parallel to liner? Drag the steps and drop them in order from start to finish Use the straightedge to draw XZ. Place the point of the compass on point M and open it to width MN. Without changing the width of the compass opening, place the point of the compass on point X and draw an arc that intersects line s. Label the intersection as point P. With the compass opening set to width MN place the point of the compass on point P and draw an arc that intersects the arc that was drawn from point X Label the intersection of the arcs as point Z. Place the point of the compass on point Y and draw an arc that intersects lines rands Label the intersections as points M and N. Use the straightedge to draw a line s that passes through X and intersects liner. Label the point of intersection as point

1. Use the straightedge to draw a line s that passes through X and intersects line r. Label the point of intersection as point Y.

2. Place the point of the compass on point Y and draw an arc that intersects lines r and s. Label the intersections as points M and N.

3. Without changing the width of the compass opening, place the point of the compass on point X and draw an arc that intersects line s. Label the intersection as point P.

4. Place the point of the compass on point M and open it to width MN.

5. With the compass opening set to width MN, place the point of the compass on point P and draw an arc that intersects the arc that was drawn from point X. Label the intersection of the arcs as point Z.

6. Use the straightedge to draw XZ.

Step-by-step explanation:

Verified correct with test results!!

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?