Solve the system of equations by substitution. x + y = 27 y = 8x

x = 0, y = 0

Step-by-step explanation:

x + y = 27y = 8x

Consider the first equation. Subtract 27y from both sides.

x + y = -27y = 0

Combine y and -27y to get -26y

x - 26x = 0

Consider the second equation. Subtract 8x from both sides.

27y - 8x = 0

To solve a pair of equations using substitution, first solve one of the equations for one of the variables. Then substitute the result for the variable in the other equation.

x - 26y = 0, -8x + 27y = 0

Choose one of the equations and solve it for x by isolating x on the left hand side of the equal sign.

x - 26y = 0

Add 26y to both sides of the equation.

x = 26y

Substitute 26y for x in the order equation,

-8x + 27y = 0.

-8 x 26y + 27y = 0

Multiply -8 times 26y

-208y + 27y = 0

Add -208y to 27y

-181y = 0

Divide both sides by -181.

y = 0

Substitute 0 for y in x = 26y. Because the resulting equation contains only one variable, you can solve for x directly.

x = 0

the probability is 0

geometry: triangles

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call the larger triangle abc

then the smaller triangle cde is similar to abc (all angles are equal, aaa).  

ab is the side that is 36, and we wish to find de, the side corresponding to ab

area_cde = area_abc - area_cde --> area_abc / area_cde = 2

let x=length of de

ratio of areas = (ratio of sides)^2

+2+=+%2836%2fx%29%5e2+

+2+=+1296%2fx%5e2+

++x%5e2+=+1296%2f2+=+648+

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