Given f(x)=(3/(x+2))-1, find f^-1(x). Need Steps.

f^-1(x) = (3/(x+1))-2

Step-by-step explanation:

First, let's replace f(x) with y, so it makes it easier to solve:

y=(3/(x+2))-1

To make a function its inverse, you replace all the x's with y's and all the y's with x's:

x=(3/(y+2))-1

Now, we need to solve for y:

x+1=(3/(y+2))

y+2=3/(x+1)

y=(3/(x+1))-2

Therefore, f^-1(x) = (3/(x+1))-2

don't know what that says sorry i can't you

step-by-step explanation:

idk what it says