Mathematics, 25.10.2020 14:40, NCT2005
Jason stands in the corner of a very large field. He walks, on a bearing of 030°, a distance of d metres. Jason then changes direction and walks twice as far on a new
bearing of 120°. At the end of the walk Jason calculates both the distance he must
walk and the bearing required to return to his original position. Given that the total distance walked is 120 metres, what answers will Jason get if he is correct?
Answers: 3
Mathematics, 21.06.2019 13:30, baca23jasmine
Ily begins solving the equation 4(x – 1) – x = 3(x + 5) – 11. her work is shown below. 4(x – 1) – x = 3(x + 5) – 11 4x – 4 – x = 3x + 15 – 11 3x – 4 = 3x + 4 how can her partial solution be interpreted?
Answers: 2
Mathematics, 21.06.2019 18:30, tyler5016
The length of a rectangle is x times the square root of 100. the width is one-half y more than three-halves x. given that the area of the rectangle is 125 cm2, which equation could represent the rectangle in terms of x and y? a) 5xy − 15x = 125 b) 5xy + 15x = 125 c) 15x2 − 5xy = 125 d) 15x2 + 5xy = 125
Answers: 2
Mathematics, 22.06.2019 00:30, aylineorozco836
If m_b=mzd= 43, find mzc so that quadrilateral abcd is a parallelogram o 86 137 o 129 43 description
Answers: 1
Jason stands in the corner of a very large field. He walks, on a bearing of 030°, a distance of d me...
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