The owner of a restaurant gathered data for several weeks about the number of first-time customers at the restaurant and the numb new memberships in the restaurant's rewards program. The data and the line of best fit are shown in the scatter plot.
-28
24
+20
New Memberships
-16
-12
10 20 30 40 50 60 70
First-Time Customers
The equation of the line of best fit is y=0.171x+ 2.241.
Could this line of best fit be used to make reasonable predictions?
OA. Yes, because the points in the plot are all very close to the line, which indicates a strong association
OB. Yes, because the slope of the line is closer to 0 than to 1, which indicates a strong association.
oc. No, because the points in the plot are all very close to the line which indicates a weak association
OD.
No, because the slope of the line is closer to than to 1, which indicates a weak association.

A. Yes, because the points in the plot are all very close to the line, which indicates a strong association

Step-by-step explanation:

Predictions that are reasonable are easier to make when the scatter plot of a data show very strong correlation relationship.

When the data points on a scatter plot are not farther from each other, and they fall almost along the line of best fit, it shows there is a strong relationship between two variables.

Therefore, it can be concluded that the line of best fit shown above can be used to make reasonable predictions because the closeness the points to the line shows that there is a strong association between number of first-time customers at the restaurant and the number of new memberships in the restaurant's rewards program.

The answer is A.

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.

bull

step-by-step explanation: