F(x) = -x^9+ 2x^2+ 8 According to the Fundamental Theorem of Algebra, this polynomial function has complex linear factors.

x=−x9+2x2+8

1

Move all terms to one side.

x+{x}^{9}-2{x}^{2}-8=0x+x9−2x2−8=0

2

No root was found algebraically. However, the following root(s) were found by numerical methods.

x=1.292229x=1.292229

c

step-by-step explanation:

there is vertical asymptote at x = 2 and x = 0

vertical asymptote occurs at the points where the denominator is 0. so we can say that

x = 2 occurs when there is a factor (x-2) in the denominator, and

x = 0 occurs when there is a factor "x" in the denominator

thus, the denominator of the equation would have "x * (x-2)", this is option c only. that's the correct answer.