In 2014, a toy store sold 12,931 stuffed animals. In 2015, the toy store sold 13,270 more stuffed animals than it did in 2014. The toy store sold the same number of stuffed animals in 2016 as it did in 2015. How many stuffed animals did the toy store sell In 2014, 2015, and 2016 combined? Find the exact answer. Solve on paper. Then check your answer on Zearn. 9 The toy store sold about 65,000 stuffed animals in 3 years. The toy store sold exactly stuffed animals in 3 years. 1 2 3 4 5 6 8 9 Enter 0 please help me!

and thanks if you can!

Arecipe uses 2 cups of sugar to make 32 brownies. how many cups of sugar are needed to make 72 brownies?

(c) compare the results of parts (a) and (b). in general, how do you think the mode, median, and mean are affected when each data value in a set is multiplied by the same constant? multiplying each data value by the same constant c results in the mode, median, and mean increasing by a factor of c. multiplying each data value by the same constant c results in the mode, median, and mean remaining the same. multiplying each data value by the same constant c results in the mode, median, and mean decreasing by a factor of c. there is no distinct pattern when each data value is multiplied by the same constant. (d) suppose you have information about average heights of a random sample of airline passengers. the mode is 65 inches, the median is 72 inches, and the mean is 65 inches. to convert the data into centimeters, multiply each data value by 2.54. what are the values of the mode, median, and mean in centimeters? (enter your answers to two decimal places.) mode cm median cm mean cm in this problem, we explore the effect on the mean, median, and mode of multiplying each data value by the same number. consider the following data set 7, 7, 8, 11, 15. (a) compute the mode, median, and mean. (enter your answers to one (1) decimal places.) mean value = median = mode = (b) multiply 3 to each of the data values. compute the mode, median, and mean. (enter your answers to one (1) decimal places.) mean value = median = mode = --

F(x) = 2x + 1? h(x) = x – h(x) = x + h(x) = x – 2 h(x) = x + 2