What is an equation for the line that passes through the coordinates (- 1, 2) and (7, 6) ?

y = 1/2x + 2.5

Step-by-step explanation:

First we want to plug it into the . This gets us 6-2/7-(-1) which solves to 4/8 which simplifies to 1/2. This gives us the slope. Now, when using slope intercept form y = mx + b, we can plug our newly found slope in for m and get y = 1/2x + b. To find b plug in any point on the line into the equation, I chose (7,6) because we are given that, and both numbers are positive. Now plug those in for x and y. 6 = 1/2(7). Solve, and get 2.5. are final equation is

y = 1/2x + 2.5

(0,-3) see attached graph

step-by-step explanation:

a. to solve the system, graph the two equations.

x = y+3 becomes y=x-3 has m=1/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move up 1 unit and 1 unit to the right. plot a point and connect.

y=-4x+3 has m =-4/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move down four units and to the right 1 unit. plot a point and connect.

the solution is the point (x,y) where the two lines intersect. by the graph below it is (0,-3).

b. to solve by substitution, substitute y = -4x-3 into x= y+3

x= (-4x-3) +3

x=-4x

5x=0

x=0

now substitute x = 0 back in to find y.

y= -4(0)-3

y=0-3

y=-3

solution is (0,-3)

c. use elimination by adding the equations together.

x-y=3

4x+y=-3

5x=0

x=0

then substitute into one equation to find y.

y=-4(0)-3

y=-3

no this is a nonlinear negative