Heres my homework 1) (3 + 2)(n+3)
2) (n-1)(2-2)
3) (2x + 3)(2x - 3)
4) (r + 1)(-3)

1. (3+2) (n+3)

= 5 (n+3)

=15n+3.

2. (n-1)(2-2)

= (n-1)0

=0

3. (2x + 3)(2x - 3)

= 4x^2 +6x -6x -9

=4x^2 -9

4. (r+1) (-3)

= -3r -3

bottom left

step-by-step explanation:

the x's and the y's both go up the same amount each time, therefore it will be a linear function because it will go in a straight line when drawn on a graph.

hope this !

the terms of a geometric sequence can be found by beginning with the first term and multiplying by the common ratio repeatedly. a recursive formula for a geometric sequence with common ratio r is given by an=ran−1 a n = r a n − 1 for n≥2 n ≥ 2 .

step-by-step explanation: