During every soccer game that Ronald plays, he runs all over the field. In his last game, he played on a soccer field that was 69,300 square feet. There are 3 feet in a yard. What is the area, in square yards (sq yd), of the soccer field where Ronald played his last game? Group of answer choices 7,700 sq yd 23,100 sq yd 207,900 sq yd 623,700 sq yd

The area of the soccer field where Ronald played his last game is 7,700 sq yd.

Step-by-step explanation:

From the question,

The area of the soccer field where Ronald played his last game was 69,300 square feet.

To determine the area, in square yards (sq yd), of the soccer field where Ronald played his last game, we will convert 69,300 square feet to square yards.

Also, from the question

There are 3 feet in a yard, that is, 3 feet = 1 yard

If 3 feet = 1 yard

∴ 3² square feet (ft²) will be equal to 1² square yard (yd²)

That is,

9 square feet = 1 square yard

Now,

If 9 square feet = 1 square yard

Then, 69,300 square feet will be

(69,300 square feet × 1 square yard) / 9 square feet = (69300/9 )square yards

= 7700 square yards (sq yd)

Hence, the area of the soccer field where Ronald played his last game is 7,700 sq yd.

the answer is two. hope this !

the answer is: d) o, f, and kr.

atomic radius of bromine (br) is 114 pm.

atomic radius of oxygen (o) is 73 pm.

atomic radius of fluorine (f) is 72 pm.

atomic radius of krypron (kr) is 112 pm.

the atomic radius of a chemical element is a measure of the size of its atom.

the atomic radius varies with increasing atomic number, but usually increases because of increasing of number of electrons.

the atomic radius decreases across the periods because an increasing number of protons, because greater attraction between the protons and electrons.