Brain liest for you7. On a hike, Peter walked 28 km in 7 h. a) What was his average rate of walking?
b) Suppose that he walked the 28 km in
8 h. What would his average rate of
walking be? do only b

a) 4km an hour

b) 3.5km an hour

Step-by-step explanation (only for b):

The answer is 3.5 kilometers because if he walked 28 kilometers in 8 hours, that means he walked an average of 28/8 km in 8/8 hours, or 3.5 kilometers in 1 hour.

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.

the answer is d. (1.2, -4.7) on edgn

hope this !