1. Write 3 quadratic equations that are NOT equivalent, each forming a graph with vertex (-2, 3).

2. Write 2 quadratic equations that are NOT equivalent, each forming a graph with x-intercepts (-3,0) and (1,0)

3. Write 1 quadratic equations that forms a graph through the points (-4,2) and (2,2) and has a maximum value at the vertex.

4. Write 1 quadratic equation that forms a graph through the points (-4,2) and (1,2) and has a minimum value at the vertex.

english, cause i can’t you

the image is given below

since the options are not given so we draw it from the equation

the given equation is

y = (x-1) (x+4)

y = y² + 3x - 4

the above equation is a quadratic equation which will have two roots. if we draw the graph for it, it will look like this

no oblique asymptote

step-by-step explanation:

to find the oblique asymptote of f(x)

here numerator has degree 1 and denomintor degree 2

degree of numerator < degree of denominator

hence there is no oblique asymptote

when the degree of the denominator > that of the numerator, we saw that the value in the denominator got so much bigger, so quickly,   giving us a horizontal asymptote of the x-axis. or we can write

f(x) = a polynomial of x + a proper fraction.

in this case only we have oblique asymptotes but not when numerator has less degree.