The equation y
=
x
+
a
y=x+ay, equals, x, plus, a is graphed in the
x
y
xyx, y-plane, where
a
aa is a positive constant. A second equation,
y
=
x
−
a
y=x−ay, equals, x, minus, a, is graphed in the same
x
y
xyx, y-plane. How do the slope and
y
yy-intercept of the graph of the first equation compare with the slope and
y
yy-intercept of the graph of the second equation?

step-by-step explanation:

4227473658779875563886538705958641728563470543621287463824132573847969p05749365273847906970680574936214

the answer is 8.64

step-by-step explanation:

$452.90 because you needed to round to the nearest cent

1) the property is   ixi = a ⇔x = a   o x = -a

4(x-5)+3= 15⇒4x-20+3 = 15⇒4x-17= 15⇒4x = 15+17⇒4x = 32⇒x =32/4= 8

4(x-5) +3= -15⇒4x-20 +3 = -15⇒4x-17= -15⇒4x =-15+17⇒4x = 2⇒x =2/4= 1/2

the values are x =8 and x = 0,5