Find the range of the function given the domain.
f(x) = x2 +2 ;D: {0, 0.25, 0.5, 0.75, 1}

{2, 2.0625, 2.25, 2.5625, 3}

Step-by-step explanation:

To find the range we can simply plug in the values of the domain and solve for the range. (The domain is the x-values)

Assuming x2 means x^2, we can plug in 0, 0.25, 0.75, 0.5, and 1 for x

0^2+2=2

0.25^2+2=0.0625+2=2.0625

0.5^2+2=0.25+2=2.25

0.75^2+2=0.5625+2=2.5625

1^2+2=1+2=3

Thus, the range is {2, 2.0625, 2.25, 2.5625, 3}

c

step-by-step explanation:

it isn't d, because the interquartile range is from 27-57. and the interquartile range is basically half the data, it's pretty obvious.

it isn't b, because like i said earlier, the interquartile range is from 27-57. 57-27 is 30. the real range has to be longer

not a either. although it looks like it, 3/4 of the data is not greater than 27. but if c is wrong than this should be correct

the correct answer is c, because 13 is the point in which the plot starts

7! = 7×6×5×4×3×2

3! = 3× 2

as 7! is multiple of 3! because 7! contains 3! that is 3× 2 as factor

so 7! /(3! ) = 7× 6× 5× 4

= 42 × 20

= 840

its b) 840✌✌✌

dhruv⭐