Which of the following equations have no solution? Check all that apply. 6x + 1 = 3(2x – 4)
2 – 5x = 7x – 12
4(3 – x) = 2(6 – 2x)
5(x + 2) = 2(x – 4)
–4(x + 3) = 4(–x – 1)

1 and 5

Step-by-step explanation:

1. 6x + 1 = 3(2x - 4)

6x + 1 = 6x - 12

6x + 13 = 6x

-6x         -6x

    13 = 0x

no solution

2. 2-5x = 7x - 12

    2 = 12x - 12

    14 = 12x

    1 1/6 = x

3. 4(3 - x) = 2(6 - 2x)

  12 - 4x = 12 -4x

    -4x = -4x

   x = ∞

4. 5(x + 2) = 2(x - 4)

   5x + 10 = 2x - 8

   3x + 10 = -8

   3x= -18

   x = -6

5. -4(x + 3) = 4( -x - 1)

   -4x -12 = -4x -4

    -4x - 8 = -4x

     -8 = 0x

  no solution

–4(x + 3) = 4(–x – 1) and 6x + 1 = 3(2x – 4)

Step-by-step explanation:

I copied the other dude

answer: a. 13/44

step-by-step explanation: judging by the information given to us, we are looking for experimental probability. we can see that 13 males have chosen chocolate ice cream. there are 44 ice creams in total (remember that the total is always the denominator). so our answer is 13/44.

what’s the question?