At noon, ship A is 50 nautical miles due west of ship B. Ship A is sailing west at 16 knots and ship B is sailing north at 15 knots. How fast (in knots) is the distance between the ships changing at 5 PM

The distance between the ships changing at 5 PM is 21.355 knots

Step-by-step explanation:

let x = distance traveled by ship A

y = distance traveled by ship B

Let z be the distance between Ship A and Ship B

Ship A is sailing west at 16 knots and ship B is sailing north at 15 knots.

Refer the attached figure

x=50+16t

y = 15t

At 5 Pm

x=50+16(5)=130

y = 15(5)=75

We will use Pythagoras theorem

At 7 pm

Differentiating both sides

Hence The distance between the ships changing at 5 PM is 21.355 knots

dalila is incorrect. the whisker on the left is very long, going all the way out to 5. the whisker goes from 5 to 30, so it has a spread of 25. the rest of the box plot values are closer together, so 5 is an outlier