A rectangular athletic field is twice as long as it is wide. If the perimeter of the athletic field is yards, what are its dimensions 76

The length is 25.3 yards, while the width is 12.7 yards.

Step-by-step explanation:

Perimeter of a rectangle, P = 2(l + w)

where l is its length and w the width.

Given that:

perimeter = 76 yards

It is twice as long as its wide, length = 2w

width = w

Then,

P = 2(l + w)

76 = 2(2w + w)

divide through by 2, to have;

38 = 2w + w

38 = 3w

⇒ w = 12.67 yards

Thus,

length = 2w = 2 x 12.67 = 25.34 yards

The length is 25.3 yards, while the width is 12.7 yards.

i = 2 / - 5

step-by-step explanation:

evaluation of ( 2 - 4 ) ( p + q ) when p = 2 and q = 5 i, by putting values of p and q,                                                                    

answer rather than having to add and subtract the measurements of the semi-circle, notice that the semicircle to the left of ad is actually identical in area to the blank semicircle-shaped space to the left of bc. so if we transferred the red semicircle into the blank space, we would end up with a square of side length 24 cm. the area of a square is s^2 = 24^2 = 676 cm^2.

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