Find the missing side and angle indicated in the picture. Round your answers to the nearest tenth. Enter your answer as equations separated by a comma.

AC = 30 in

m∠B = 36,9°

m∠A = 53,1°

Step-by-step explanation:

1 AC

You gan get AC with the pythagorean theorem:

a²+b²=c²

We are looking for side b of the triangle, so the equation is rearranged for b.

BC²+AC²=AB²    | -BC²

AC²=AB²-BC²

AC=√(AB²-BC²)

Now the given values are used:

b=√(50²-40²)

b=√(2500-1600)

b=√900

b=30 in

2 m∠B

This angle can be calculated using the sine law:

sine(angle)=opposite cathete/hypothenus

We are looking for angle m∠B of the triangle.

sin(m∠B)=AC/AB

sin(m∠B)=30in/50in

sin(m∠B)=0,6

m∠B=36,9°

3 m∠A

This angle can be calculated using the sine law:

sine(angle)=opposite cathete/hypothenus

We are looking for angle m∠A of the triangle.

sin(m∠A)=BC/AB

sin(m∠A)=40in/50in

sin(m∠A)=0,8

m∠A=53,1°

part a

answer: a reasonable domain is where n is a real number. so n can be between 0 and 10. both endpoints are included.

work shown:

n is the number of days after the experiment starts. the smallest n can be is n = 0 which means that 0 days have gone by, and we're at the start. to find out how large n should be, then replace f(n) with 16.13 and solve for n. use logarithms to isolate the exponent.

f(n) = 12*(1.03)^n

16.13 = 12*(1.03)^n

16.13/12 = (1.03)^n

1.34416666666667 = (1.03)^n

(1.03)^n = 1.34416666666667

log[ (1.03)^n ] = log[ 1.34416666666667 ]

n*log[ 1.03 ] = log[ 1.34416666666667 ]

n = log[ 1.34416666666667 ]/log[ 1.03 ]

n = 10.0062999823929

this rounds to n = 10 which is fairly close but not 100% perfect. so this is the largest n can be.

note: if you plug n = 10 into f(n), you'll get roughly 16.127 which rounds to 16.13 (this comes up again in part c)

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part b

answer: the y intercept is 12. it represents the starting height of the plant in cm.

work shown:

plug n = 0 into the f(n) function. simplify

f(n) = 12*(1.03)^n

f(0) = 12*(1.03)^0

f(0) = 12*(1)

f(0) = 12

on day n = 0, aka the starting point, the height f(n) is 12 cm

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part c

answer: the average rate of change is approximately 0.43061036458991 (round however you need to). this represents the average growth rate from day n = 3 to day n = 10. so the plant grew roughly 0.43 cm per day during this timespan, assuming you round to 2 decimal places.

work shown:

compute f(3)

f(n) = 12*(1.03)^n

f(3) = 12*(1.03)^3

f(3) = 13.112724 < we'll use this later

compute f(10)

f(n) = 12*(1.03)^n

f(10) = 12*(1.03)^10

f(10) = 16.1269965521294 < we'll use this later

now use the formula below with a = 3 and b = 10

aroc = average rate of change

aroc = [ f(b) - f(a) ]/[ b - a ]

aroc = [ f(10) - f(3) ]/[ 10 - 3 ]

aroc = (16.1269965521294 - 13.112724)/(10 - 3)

aroc = 3.0142725521294/7

aroc = 0.43061036458991

round this however you need to

note: the plant grew approximately 3.01 cm over 7 days, so roughly 0.43 cm per day is the average growth rate (if you were to round to 2 decimal places).