S is the midpoint of RT. RS=x2 and ST= 8-2x. Find both values of x.

x = -4 or 2

Step-by-step explanation:

We are told that S is the midpoint of RT.

Thus; RS = ST.

Now we are told that RS = x² and ST = 8 - 2x

Thus;

x² = 8 - 2x

x² + 2x - 8 = 0

Using quadratic formula;

x = [-2 ± √(2² - 4(1 × - 8))]/(2 × 1)

x = (-2 ± √36)/2

x = (-2 ± 6)/2

x = -4 or 2

δabc ≅ δdcb by sas because

db ≅ ac . . given (side)

bc ≅ bc . . reflexive property (side)

∠dbc ≅ ∠ acb . . alternate interior angles where transversal bc crosses parallel lines bd and ac (included angle)

there is no points to select.

step-by-step explanation: