Ronald has a 10% solution of the fertilizer Super Grow. How much pure Super Grow should he add to the mixture to get 36 oz of a 12.5% concentration?

1 oz

Step-by-step explanation:

Given that:

% solution of super grow fertilizer = 10%

To obtain mixture of 36oz of a 12.5% concentration

Let oz of pure supergrowth to be added = s

(Initial % * (36 - s) + s) / 36 = target concentration

(10% * (36 - s) + s) / 36 = 12.5%

(0.1(36 - s) + s) / 36 = 0.125

Cross multiply:

0.1(36 - s) + s =. 0.125 * 36

3.6 - 0.1s + s = 4.5

3.6 + 0.9s = 4.5

0.9s = 4.5 - 3.6

0.9s = 0.9

s =. 0.9/0.9

s = 1

Hence, 1 oz of pure supergrowth should be added to the 10% solution to get 36 oz of a 12.5% concentration.

since your problem is x^4 = 81, what you have to undeo is the "to the fourth power" part.

the inverse (opposite operation) of "to the fourth power" is "to the fourth root".

  (x^4) ^ ¼   = 81 ^ ¼  

  81 = 3^4     so (3 ^ 4) ^ ¼   =   3 ^ 1   = 3

by hand: (3 ^ 4) ^ ¼   =   3 ^ (4 x ¼) = 3 ^ 1   = 3   (when you take a power to a power, multiply the exponents.)

or, do it by calculator. one way of finding the fourth root is to use ^ (1/4)

step-by-step explanation:

step-by-step explanation:

this is not a question