Rectangles P, Q, R, and S are scaled copies of one another. For each pair, decide if the scale factor from one to the other is greater than 1, equal to 1, or less than 1.

The image showing the complete question is attached.

1) Scale factor = 2

2) Scale factor = 4

3) Scale factor = ½

4) Scale factor = 2

5) Scale factor = 1

6) Scale factor = ¼

7) Scale factor = 1

Step-by-step explanation:

Scale factor is a number by which the dimensions of an object are multiplied in order to create an enlarged or reduced object.

Now, from the image attached;

1) From P to Q, we see that the length of Q seems to be double that of P. Similarly, the width of Q seems to be double that of P. Thus, each dimension of P is said to be multiplied by 2 to achieve the enlarged dimensions of Q.

Thus, scale factor = 2

2) From P to R, we see that the length of R seems to be 4 times that of P. Similarly, the width of R seems to be 4 times that of P. Thus, each dimension of P is said to be multiplied by 4 to achieve the enlarged dimensions of R.

Thus, scale factor = 4

3) From Q to S, we see that the length of S seems to be half of that of Q. Similarly, the width of S seems to be half of Q. Thus, each dimension of Q is said to be multiplied by ½ to achieve the reduced dimensions of S.

Thus, scale factor = ½

4) From Q to R, we see that the length of R seems to be double that of Q. Similarly, the width of R seems to be double that of Q. Thus, each dimension of Q is said to be multiplied by 2 to achieve the enlarged dimensions of R.

Thus, scale factor = 2

5) From S to P, we can see that the dimensions of both rectangles remain the same. Thus, S was multiplied by a factor of 1 to get P. Scale factor = 1

6) From R to P, we see that the length of P seems to be a quarter that of R. Similarly, the width of P seems to be quarter of R. Thus, each dimension of R is said to be multiplied by ¼ to achieve the reduced dimensions of P.

Thus, scale factor = ¼

7) From P to S, we can see that the dimensions of both rectangles remain the same. Thus, P was multiplied by a factor of 1 to get S. Scale factor = 1

distance covered by pamela in 9 l of fuel = 99km

let us apply unitary method here.

distance covered by pamela in 1 l of fuel =99/9 =11 km

now let us find distance covered by pamela if she has 12 l of fuel.

distance covered in 12 l = distance covered in 1 l of fuel * 12

we know that distance covered by here in 1 l is 11 km.

so distance covered in 12 l of fuel = 11*12 = 132 km.

(2x + 16) + (x) = 180

step-by-step explanation:

given,

abcd is a quadrilateral inscribed in a circle

angle a is labeled x plus 16, (x + 16)

angle b is labeled x degrees, (x)

angle c is labeled 6x minus 4, (6x – 4)

angle d is labeled 2x plus 16, (2x + 16)

what equation can be used to solve for angle b?

we know that the sum of the opposite angles of a simple quadrilateral inscribed in a circle is 180 degrees.

angle b is opposite angle d

therefore, angle b + angle d = 180

(x) + (2x + 16) = 180 

same as (2x + 16) + (x) = 180