Number 2 please help quick .Asap

Problem 2, Part (a)

A = event elevator's 1st stop at the 2nd floor

P(A) = 3/4

Since the elevator needs to go up one floor

B = event elevator has its 2nd stop at the 3rd floor

P(B given A) = probability event B happens given event A happened

P(B given A) = 3/4

P(A and B) = P(A)*P(B given A)

P(A and B) = (3/4)*(3/4)

P(A and B) = 9/16

Problem 2, Part (b)

A = event elevator's 1st stop at the 2nd floor

P(A) = 3/4

B = event elevator has its 2nd stop at the 3rd floor

P(B given A) = 3/4

C = event elevator has its 3rd stop at 4th floor

P(C given (A and B)) = 3/4

P(A & B & C) = P(A)*P(B given A)*P(C given (A and B))

P(A & B & C) = (3/4)*(3/4)*(3/4)

P(A & B & C) = 27/64

Problem 2, Part (c)

A = event elevator's 1st stop at the 2nd floor

x = P(A) = 3/4

B = event elevator has its 2nd stop at the 3rd floor

y = P(B given A) = 3/4

C = event elevator has its 3rd stop at 2nd floor

z = P(C given (A and B)) = 1/4

D = event elevator has its 4th stop at 1st floor

w = P(D given (A & B & C)) = 1/4

P(A & B & C & D) = x*y*z*w

P(A & B & C & D) = (3/4)*(3/4)*(1/4)*(1/4)

P(A & B & C & D) = 9/256

∠lno ≅ ∠lnm

∠oln ≅ ∠mln

step-by-step explanation:

given   that triangle lno is congruent to triangle lnm.

we have to fill up the blanks in the given question.

according to above order of congruency   kept in mind we can say that

∠lno ≅ ∠lnm

∠oln ≅ ∠mln

ln ≅ ln due to common in both.

hence, by sas congruency,

the side angle side rule   states that if two sides and the included angle of one triangle are congruent to another triangle, then these two triangles are congruent.

c 1 hour

step-by-step explanation:

m = 2e

m = 2 so 2 = 2e

1 = e