A(n)=2+(n-1)(3) find the fourth and tenth term of the sequence

The fourth term is 11 and the tenth term is 29

Step-by-step explanation:

Let us use the given formula to solve the question

∵ A(n) = 2 + (n - 1)(3) is the formula of the nth term of an sequence

∵ n is the position of the term in the sequence

∴ For the fourth term n = 4

∴ For the tenth term n = 10

→ Substitute n by 4 in the formula above to find the fourth term

∵ A(4) = 2 + (4 - 1)(3)

∴ A(4) = 2 + (3)(3)

∴ A(4) = 2 + 9

∴ A(4) = 11

∴ The fourth term is 11

→ For the tenth term put n = 10

∵ n = 10

∵ A(10) = 2 + (10 - 1)(3)

∴ A(10) = 2 + (9)(3)

∴ A(10) = 2 + 27

∴ A(10) = 29

∴ The tenth term is 29

i believe it is c.y = 9x

rise over run. 9 units up over 1 unit right or 9/1

a = 3.14

b = 18

c = 18/5 or 3.6 or 3 3/5

step-by-step explanation: