Every rope has a safe working load. A rope should not be used to lift a weight greater than its safe working load. The table shows the safe working loads $S$ (in pounds) for ropes with circumference $C$ (in inches). Write an equation for the safe working load for a rope. Find the safe working load for a rope that has a circumference of 10 inches.

the equation is:

f(x) = 180x²

the maximum working load for a 10 inch rope = 180 · 10² = 18,000 pounds

Step-by-step explanation:

the table is missing, so I looked it up:

inches             safe working load

0                             0              

1                            180          

2                           720          

3                          1620        

180 is their common denominator:

0                      0                        0

1                      180                      1

2                     180                      4

3                     180                      9

1, 4, and 9 follow a pattern x²:

0                   0

1                    1

2                   4

3                   9

4                  16

5                  25

6                  36

7                  49

8                  64

9                  81

10                100

answer:   35 % is the probability of a late departure or an early arrival.

step-by-step explanation:

let l represents the late departure and e represents the early departure.

then, according to the question,

p(l) = 12 %,   p(e) = 27 % and = 4 %

and, we have to find out,

but, we know that,

which is the required equation that will use to find the probability of a late departure or an early departure.

therefore,   the probability of a late departure or an early arrival =   35 %

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