Write the equation of the line in slope-intercept form.

y = -½x + 3

Step-by-step explanation:

The equation of a line in slope-intercept form is

y = mx + c

where m is the gradient (slope) and c is the y-intercept

We can find the gradient and intercept from the two points on the diagram

The points are:

(0, 3) and (4, 1)

The y-intercept is when x = 0

we are already given this point so

c = 3

now we can use our other point to find m. So:

1 = 4m + 3

-2 = 4m

-½ = m

Now we can put both variables into our slope-intercept form

y = -½x + 3

x = ±sqrt(10)

step-by-step explanation:

5 - 2x² = -15

subtract 5 from each side

5-5 - 2x² = -15-5

-2x^2   = -20

divide by -2 on each side

-2x^2   /-2= -20/-2

x^2 =10

take the square root on each side

sqrt(x^2 )=±sqrt(10)

x = ±sqrt(10)

check:

5 - 2x² = -15

+sqrt(10)

5 - 2(sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

-sqrt(10)

5 - 2(-sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

40 i don’t know lololol