(-m2 + 6) + (-4m2 + 7m + 2) =

−5m² + 7m + 8

Explanation:

−m² + 6 − 4m² + 7m + 2

= −m² + 6 + −4m² + 7m + 2

[ Combine Like Terms ]

= −m² + 6 + −4m² + 7m + 2

= ( −m² + −4m²) + (7m) + (6 + 2)

= −5m² + 7m + 8

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.

step-by-step :