Use the three steps to solve the problem.
the sum of 3 consecutive integral numbers is 117. find the numbers.

If the second of the three numbers is  

n

, then the first and third are  

n-  1 and  n + 1 , so we find: 117 = ( n − 1 ) + n + ( n + 1 ) = 3n  

Dividing both ends by  

3  we find: n = 117/  3   = 39

So the three numbers are:

38 , 39 , 40

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step-by-step explanation:

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