HELP ME PLEASE. ASAP. Use the given information to complete parts I and II. In your final answer, include all calculations. Mars has an approximate diameter of 6.794 · 10 9 millimeters. The sun has a diameter of 1.391 · 10 6 kilometers.

Part I: Given that for every one kilometer there are 1,000,000 millimeters, which unit of measurement should be used to best represent the lengths of the sun and Mar's diameters?

Part II: Use estimation to approximate how many times greater the sun’s diameter is than planet Mars’s.

n to complete parts I and II. In your final answer, include all calculations.

Mars has an approximate diameter of 6.794 · 10 9 millimeters. The sun has a diameter of 1.391 · 10 6 kilometers.

Part I: Given that for every one kilometer there are 1,000,000 millimeters, which unit of measurement should be used to best represent the lengths of the sun and Mar's diameters?

Step-by-step explanation:

529 and 531

step-by-step explanation:

second option

step-by-step explanation:

the measures of a triangle equal 180. use that to find x.

2x+3x+4x=180

9x=180

9x/9=180/9

x=20

now you know x, you know angle a is 40°, angle b is 60°, angle c is 80°.

because angle a is 40°, the first option doesn't work.

because angle b is 60°, the second option does work.

when you add angle a and b, you get 100°. complementary means it equals 90°, so the third option doesn't work.

when you add angle a and c, you get 120°, which is not 100.