Lewis is rolling a 10-sided die 250 times. each side of the die is labeled with a number 1 – 10. based on the theoretical probability, how many times would lewis be expected to roll a multiple of 3?

Number of times would Lewis be expected to roll a multiple of 3 = 75

Step-by-step explanation:

Multiples of 3 in 1 to 10 are 3,6 and 9

So we are having 3 multiples of 3 in 1-10

Probability of an event is the ratio of number of favorable outcome to the total number of outcomes.

Probability to roll a multiple of 3

Total number of rolling = 250

Based on the theoretical probability, number of times would Lewis be expected to roll a multiple of 3 = Total number of rolling x Probability to roll a multiple of 3

Number of times would Lewis be expected to roll a multiple of 3

d. 8

step-by-step explanation:

the given radical expression is:

we can rewrite this as:

we express as square numbers to get;

the exponents will now cancel out to give.

the correct answer is d

the answer is 1/4

step-by-step explanation: