PLSSS HELP WILL GIVE BRAINLIEST IF CORRECT Two-thirds of the dairy cattle on a farm are in the barn. One-fourth of the beef cattle are in the barn. There are 24 dairy cattle and 16 beef cattle in the barn. How many more beef cattle are on the farm than dairy cattle?

There are ? more beef cattle on the farm than dairy cattle.

There are 28 more beef cattle on the farm than dairy cattle.

Step-by-step explanation:

Let  d = the total number of dairy cattle

b = the total number of beef cattle

2/3 of the dairy cattle on a farm are in the barn, and we know that 24 dairy cattle are in the barn thus:

(2/3)d = 24

d = 36 dairy cattle

1/4 of the beef cattle are in the barn and there are 16 beef cattle in the barn thus:

(1/4)b = 16

b = 64 beef cattle

64 - 36 = 28

There are 28 more beef cattle on the farm than dairy cattle.

28 more beef cattle.

Step-by-step explanation:

Do 16*4 since 1/4 = 16 beef cattle. 16*4=64 total beef cattle on the farm.

Then do if there are 24 dairy cattle in the barn and that is 2/3 of all the cows.

1/3 = 12 so the total number of dairy cows on the farm is 12*3=36

Now subtract 64-36=28

There are 28 more beef cattle than dairy cows.

Hope this Helps!!

d. 24+-0.114

step-by-step explanation:

the question requires us to calculate the approximate 95% confidence interval for the mean number of ounces of ketchup per bottle in the sample given the following statistics;

sample mean = 24

standard deviation, σ = 0.4

sample size , n = 49

the confidence interval for a population mean is calculated using the formula;

sample mean ± z-score*(σ/sqrt(n))

the z-score associated with a 95% confidence interval, from the standard normal tables, is;

1.96

substituting these values into the formula;

24 ± 1.96*(0.4/7)

= 24 ± 0.112

from the alternatives given, choice d is closest to the above expression;